Webb7 apr. 2024 · Here we have the periodic function is $f(x) = 3\cos 5x$ The formula for the period of the function is $T = \dfrac{{2\pi }}{a}$. From given function, $a = 5$ Hence the … WebbSo we're just going to be left with a negative 5 sine of 5x minus 3y. And we're in the home stretch now. To solve for dy/dx, we just have to divide both sides of the equation by this. And we are left with dy/dx is equal to this thing, negative 5 times the sine of 5x minus 3y. All of that over 1 minus 3 sine of 5x minus 3y. And we are done.

Find Amplitude, Period, and Phase Shift y=2sin(5x) Mathway

WebbMedium Solution Verified by Toppr Period = π Explanation : If we express the cosine function in the following way : y=acos(bx+c)+d Then: ∣a∣ = the amplitude ∣b∣2π = the period b−c = the phase shift d = the vertical shift For given function we have : ∣b∣=2 So period is : 22π=π The graph confirms this: Was this answer helpful? 0 0 Similar questions WebbThe function y = cos x y = cos x is one-to-one on [0, π]; [0, π]; thus, this interval is the range of the inverse function of y = cos x, f (x) = cos − 1 x. y = cos x, f (x) = cos − 1 x. 3 . π 6 π 6 is the radian measure of an angle between − π 2 − π 2 and π 2 π 2 whose sine is 0.5. resin infused wood

What is the period of $y = 3\cos 5x$ - Vedantu

WebbChoose the correct equation for the function whose graph is shown. y=9/5sin6x What is the correct equation for the function whose graph is shown? y = -3 cos 5 x Which function has a period equal to half the period of the function in etc... y=5sin (6x/5x-pi)-4 Other sets by this creator Quiz 2 of Finance 33 terms king_boozy1 11 terms king_boozy1 WebbPeriod = πExplanation :If we express the cosine function in the following way :y=acos(bx+c)+dThen:∣a∣ = the amplitude∣b∣2π = the periodb−c = the phase shiftd = the … resin infusion